Sunday, December 8, 2024

NEW WAY OF SQUARING NUMBERS


https://youtu.be/gJ44CC5MfHU?si=k6dZ5b5PtR2G-df5



Common Way of Multiplying Numbers


Squaring a number is the same as multiplying two numbers having identical values.


Example:

Square the number 743 = 743x 743.


1) Multiply 743 by 3. Put the carries above 743 and the partial product = 2229

2) Then multiply 743 by 4. The partial product = 2972. Put the last digit 2 on the tens decimal place.

3) Lastly, multiply 743 by 7. the partial product = 5201. Put the last digit 1 on the hundreds decimal place.

4) Add the partial products and what we get is = 552049 or 552,049


That is how we commonly get the square of a number.


Systematic Squaring Method (SSQ)


This time, I’ll teach a new way of getting the squares of numbers in an easier and orderly manner. But first, you must also know some new things.


Digit Number


A digit (what I’m talking about here is the numeric digit), is either any of the following;


0, 1, 2, 3, 4, 5, 6, 7, 8 or 9


A number such as 743 has three digits, 7, 4 and 3. Sometimes it is called a three-digit number. All you have to do is to count the digits. Counting the digits of 4,569,742, we can then, name that number, as a seven-digit number. In SSQ, the “count of digits of a number is important”. Later, you will realize the reason why it is important. But for now, giving you the idea of what a digit of a number is all about, would be enough.


Meaning of SSQ

SSQ stands for Systematic Squaring. It is based on a popular algebraic equation, (X + Y)2. It is much different from the common method of multiplying two identical numbers.

SSQ has four main parts, namely:


1) PSL (Partial Squares Line)

2) Sub-products (SP1, SP2, SP3…)

3) Sub-totals (ST1, ST2, ST3…)

4) Total Sum (TSum)


Index Squares


Always remember that there are only ten basic digits (numeric digits) and these are;


0, 1, 2, 3, 4, 5, 6, 7, 8 and 9


An index square is a product of a ‘basic digit’ multiplied by itself:


0x0 = 0 / 1x1 = 1 / 2x2 = 4 / 3x3 = 9 / 4x4 = 16


5x5 = 25 / 6x6 = 36 / 7x7 = 49 / 8x8 = 64 / 9x9 = 81


It is safe to call 0, 1, 4, 9, 16, 25, 36 , 49, 64 and 81 as index squares but in SSQ, an index square must be expressed as “two-digit square”. So the proper way of writing them as follows;


Table of Index Squares


02 = 00

12 = 01

22 = 04

32 = 09

42 = 16

52 = 25

62 = 36

72 = 49

82 = 64

92 = 81



Two-Digit Systematic Squaring (2D.SSQ)


Let start by squaring a two-digit number, using the SSQ method


Question: What is the square of 23?

232 = ?


Step 1: Create a PSL


Partial Squares Line (PSL)


The PSL is simply, the “two-digit squares” representation of each, individual digits of a certain number. In 232, the two-digit squares representation of the digits, 2 and 3 are 04 and 09, respectively. So we simply write it this way:


232 = 04’09 ← PSL


But don’t forget to also include this sign - ’ (a special character called single close quote). It will easily give us a clue of how many index squares are there in a PSL.


Step 2: Solve the sub-product


Sub-Product (SP1)


Don’t think that the value we’d taken from the PSL is already the correct answer. The value 04’09 is still incomplete. We must add a sub-product to come up with the ‘true’ square value of 23. But to get the sub-product of 23, we must cross multiply the digits 2 and 3 in a certain kind of pattern.


General Rules in Dealing with Sub-products


Rule 1: Cross multiply the individual digits of a given number using the R.A.R. multiplication pattern


Rule 2: Don’t forget the DTP reminder, “Double The Product


Rule 3: Follow the decimal place of the reference digit


R.A.R. Multiplication Pattern


R.A.R. stands for “Reference Digit and All the Digits to the Right”. It is a multiplication pattern that is effective in solving the sub-products. How it works?


First Pattern:


If we pick 3 from 23 as our reference digit, ‘the all to the right’ of 3 is nothing, null, empty or zero. Multiplying 3 by 0 is futile, so, we can skip this pattern.


Second Pattern (SP1):


If we pick 2 as our reference digit, ‘the all to the right’ of 2 is 3.


Rule 1: 2 x 3 = 6


Rule 2: DTP reminder 6 x 2 = 12

If you wish, you can skip rule 2 as long as you directly multiply 2 x 3 by 2


2x3x2 = 12 ← SP1


Rule 3: Our reference digit 2 is in the tens decimal place, therefore, the last digit of SP1 must be also, in the tens decimal place


2x3x2 = 12 ← SP1 (provided that 2 of 12 is aligned to the tens decimal place)



Step 3: Get the total sum, add the sub-product to the PSL


Total Sum


The total sum is the final answer. It reflects the ‘true’ square value of a given number. If you multiply 23 by 23, using the common method of multiplying numbers, you will discover that the total sum of SSQ method is exactly equivalent to the product of 23 x 23.


T-Sum = PSL + SP1


... 232 = 04’09 ← PSL
+2x3x2 = 1'2 ← SP1

..............05’29 ← T-Sum




GETTING SQUARE ROOTS OF LARGE NUMBERS QUICK AND EASY (EIGHT DIGITS) by ...

Saturday, November 23, 2024

MY SQUAREROOT DISCOVERY by sirjon PART 2


This is it. Get a calculator. Press three digits number and multiply by itself.
Then amaze your friends that you can find it's square root just in seconds.
So, forget the long-hand division.

Sunday, December 19, 2010

I already created two blogs about this topic but I realized that my approach or method of explaining them to my readers seems to be difficult to comprehend (or a little bit complicated to understand). So, I decided to create a better, simple presentation of taking the square root of any number, much better than the usual method taught in schools.

Example, let’s take the square root of 7

√7 = ?

The number 7 is not a ‘perfect square’ number. It is in-between the square of 2, (22 = 4) and the square of 3 (32 = 9).

But we choose 2 as our first digit. (It the nearest but lesser than 7)

_2

√7


But to say that the square root of 7 is 2 is wrong (since we know that the 2 is the square root of 4). It is more acceptable to say that the square root of 7 is about “two point something” (or written as 2.- - - ). But the question is, what is that “point something”?

THE NEXT DIGIT

Okay, put another two zeroes after 7, indicating that we’re intended to know ‘what’ that “point something” is.

_2.___

√7.00

If you will notice, 7.00 is in-between 22 (which is, 4) and 32 (which is, 9).

32 = 9.00

?2 = 7.00

22 = 4.00

Now, in-between 2 and 3 are the following –

2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, and 2.9

Or we can represent them this way:

(Table 1)

3.02 = 9.00

2.92 = …

2.82 = …

2.72 = …

2.62 = … (The square root of seven or 7.00 is “within” these

2.5 2 = … numbers in-between 3.002 and 2.02)

2.4 2 = …

2.32 = …

2.22 = …

2.12 = …

2.0 2 = 4.00

We have nine choices and only one of them is the ‘nearest’ square root of 7.

Middle-Half Square

One way to know the next digit after the first digit “2” in our attempt to take the square root of 7.00 is to know first, the middle- half square of 2.0 and 3.0

3.02 = 9.00

2.52 = …?

2.02 = 4.00

There is a technique in knowing the “

"square of a two-digit number ending in five”

.

3.02 = 9.00

2.52 = 6.25

2.02 = 4.00

Now, 7.00 is above the middle half square 6.25 but below 9.00. So, our choices for the nearest possible square root of 7.00 (in a two-digit representation), are the following:

2.6, 2.7, 2.8, and 2.9

Or we can represent them this way:

(Table 2)

3.02 = 9.00

2.92 = …

2.82 = … (The square root of seven or 7.00 is “within” these

2.72 = … numbers in-between 3.002 and 2.52)

2.62 = …

2.5 2 = 6.25

We cut down our choices from nine into four and ‘only one’ is the nearest possible square root of 7.00

Quarter Part Square

We can still cut down the four choices into two. How? Simply add the lower square “L” (this time, it is 6.25) to the higher square “H” (that is, 9.00) and then divide by two.

H = 9.00

L = 6.25 (Add)

S =15.25 ÷ 2 = 7.625 (The “S” stands for Sum)

Some Adjustments

The quotient 7.625 is a little bit higher than the actual square of 2.752, which is equal to 7.5625.

Why 2.752? The middle-half square value between 2.52 and 3.02 is 2.752, which happens

to be the “upper-quarter part square value” between 2.02 and 3.02.

(Table 3)

3.02 = 9.00

2.92 = …

2.82 = …

2.752 = 7.5625 ← upper-quarter part square or “UQS”

2.72 = …

2.62 = …

2.5 2 = 6.25 ← Middle-Half Square

Some modifications should be made to make our computation (getting the upper part square value), much nearer to the actual value without directly squaring it (remember, 2.752 is a three-digit number, squaring it is a little bit difficult). Using the method of “add then divide by two” as shown above (also known as taking the average or median of two adjacent numbers), two more things you should remember to do:

Step 1: Ignore the last digit 5. In the case of the quotient 7.625, simply ignore or delete the last digit 5. So, the number will appear as 7.62

Step 2: Always subtract by the “adjustable 6”. This step does not follow the strict rule in math of putting the 6 in its proper decimal place. Simply subtract the quotient which in this case equal to 7.62 by ..6 (represented as “two dots before the number six). Simply put the 6 in the same decimal place as to the last digit.

7.62 - ..6 = 7.56

The value 7.56 has an error of only .0025 which is negligible (compare to the actual square value of 2.75 which is exactly equal to 7.5625).

If you look at Table 3, you will notice that the upper-quarter part square 7.56 is above or greater than 7.00. Therefore, the two remaining choices will be 2.62 and 2.72:

(Table 4)

2.752 = 7.5625

2.72 = … (The square root of seven or 7.00 is “within” these

2.62 = … numbers in-between 2.52 and 2.752)

2.5 2 = 6.25

Two-Digit Squaring

Now, let us square the two remaining choices and look which of the two is the nearest possible square root of 7.00 using the

SSQ method.

2.72 = 04’49 PSV (Partial Square Value)

2x14= 2’8 . Add SP (Sub-product)

Ans.= 07.29

We cannot take 2.7 as the square root of 7.00 (in two-digit representation) because it is “over” or greater than 7.00 (The more preferred answer is nearest but less than 7.00)

2.62 = 04’36 PSV (Partial Square Value)

2x12= 2’4 . Add SP (Sub-product)

Ans.= 06.76

The answer 6.76 is the nearest but lesser than 7.00. Therefore, we choose 2.6 or simply the digit “6” as our next digit after writing the first digit “2”

_2. 6___

√7.00

THE NEXT DIGIT (PART II)

If you intend to continue, simply put another two zeroes after 7.00.

_2. 6___

√7.00’00

Now, we’re going to represent the square root of 7 (or 7.00’00), into three-digit number (of course, with respect to the decimal point).

Middle-Half Square (Part 2)

Again, 7.00 is in-between 2.72 and 2.62.

2.702 = 7.29 (or 7.29’00)

2.652 = …?

2.602 = 6.76 (or 6.76’00)

There are two ways we can determine the middle-half square (which is 2.652):

First: “Add Then Divide By 2” Method

2.72 = 7.29

2.62 = 6.76 (Add)

Sum=14.05 ÷ 2 = 7.02

2.652 = approx. 7.02

Second: “Innovative” Technique which I called “Paste and Copy” (sounds familiar?)

How it works? You will notice that our latest nearest possible ‘square root’ of 7 is 2.6.

Step 1:

Simply write down again the square of 2.6 (latest nearest square root value)

2.62 = 6.76

Step 2:

Put (or paste) a “5” after 2.6 and paste “25” after 6.79

2.652 = 6.76’25

Step 3:

Copy the digits ‘2’ and ‘6’ or ‘26’ (ignore the decimal point) and put it below 6.79’25,

Placing the last digit of 26 ‘aligned’ to the digit before the last two digits of 6.79’25 (which happens to be ‘25’).

2.652 = 6.76’25 ← paste 25 here

+(copy)= 26 .

Ans.. = 7.02’25

2.702 = 7.29 (or 7.29’00)

2.652 = 7.02’25

2.602 = 6.76 (or 6.76’00)

You will notice that 7.02’25 is above 7.00’00, so the next nearest possible square root of 7 is below 2.65 (It could either be 2.64, 2.63, 2.62 or 2.61)

Quarter Part Square (2nd time)

We do this part to cut down our choices from four into only two choices

Let us apply the ‘Add and Then Divide By Two” Method:

H = 7.02’25

L = 6.76 . ← Add

S =13.78’25 ÷ 2 = 6.89’12’5

2.6252 = 6.89’12’5 (approximate value only)

Note: The actual square value of 2.625 (that is, 2.6252 = 6.89’06’25) is much lower by 0.000625, which can be considered negligible.

We can also call “2.6252 = 6.89’12’5 as LQP Square (Lower-Quarter Part Square)

(Table 5)

2.652 = 7.05’25

2.642 = … (The square root of seven or 7.00 is “within” these

2.632 = … numbers in-between 2.652 and 2.6252)

2.62252 = 6.92’12

2.622 = … (Ignore these lines below 2.62252)

2.612 = …

2.602 = 6.76 (or 6.76’00)

So, we cut down our choices into two and only one of them is ‘acceptable’

To find out the square of 2.64 the easier way, simply do the “

L.A.L. Squaring Method

2.642 = (2.62)’16 ← PSV (partial square value)

26x..8 = ..208 ← Add this SP (provided that it is in its proper decimal place)

TSum = 6.76’16 + ..208 = 6.9696

We can write them down this way:

2.642 = 6.76’16 PSV

26 x..8 = 20’8 . PS (Add)

Ans.. = 6.96’96

There’s no need to ‘test’ the second choice (2.632), because it is obvious that its square value is much lower than 2.642.

Therefore, we choose 2.64 as the nearest possible square root of 7.00 or to be more specific, we choose the digit ‘4’ as our third digit.

_2. 6 4___

√7.00’00

Again, if you wish to continue, just repeat the process above…that is, put another two zeroes, find the middle-half square value, determine the quarter-part square (either UQP or LQP) and do the ‘square sampling’ of the two remaining choices and so on and so on.